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-4y^2-13y-9=0
a = -4; b = -13; c = -9;
Δ = b2-4ac
Δ = -132-4·(-4)·(-9)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*-4}=\frac{8}{-8} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*-4}=\frac{18}{-8} =-2+1/4 $
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